Neoclassical Growth Model 笔记
Ramsey model
preliminaries
\[H={1,2,...,M} \ with \ M=\infty\]Time Separable Preferences
\[u_{i}(c_{i,t})\]Infinite Horizon and the Representative Household
行为经济学 hyperbolic discounting
von Neumann-Morgenstern expected utility function:
\[E^{i}_{0}\sum^{T}_{t=0}\beta^{t}_{i}u_{i}(c_{i,t})\]Preferences, Technology and Demographics
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- Representative household with instantaneous utility function $u({c_{t}})$ Assumption, u (c) is strictly increasing, concave, twice continuously differentiable with derivatives u′and u′′, and satisfies the following Inada type assumptions: $lim_{c→0 } u’(c) = ∞; lim_{c→∞} u’(c) = 0$
- Suppose representative household represents set of identical households (normalized to 1).
- Each household has an instantaneous utility function given by the above utility function.
- $L {0}= 1 \ and \ L{t}= exp (nt)$
where $c_{t}$ consumption per capita at t, ρ is the subjective discount rate, and effective discount rate is ρ − n
- Continues time analogue of $\sum^{\infty}{t=0}\beta^{t}{i}u_{i}(c_{i,t})$
- Objective function (1) embeds
- (a) Household is fully altruistic towards all of its future members, and makes allocations of consumption (among household members) cooperatively.
- (b) strictly concave of u (·)
- each household member $c_{t}≡\left( \frac{C_{t}}{L_{t}} \right)$
- at time t, total of $L_{t}u(c_{t})=\exp(nt)u(c_{t})$
- With discount at rate of $exp {(−ρt)}$, obtain (1)
- assumption: ρ > n
- Production possibilities set of the economy:
- 在 solow 模型里一样的
- Denote asset holdings of the representative household at time t by $A_{t}$
- The total net supply of bonds is zero in a closed economy without government
- market clearing:
资产的无风险回报率:$r_{t}=R_{t}-\delta$
budget constraint
\[\dot{a_{t}}=(r_{t}-n)a_{t}+w_{t}-c_{t}\tag{3}\]is a flow constraint
focused on No Ponzi Game Condition
The No Ponzi Game Condition
- finite: $a_{T}=0$
- infinite: 现值=0
这个式子的意思是折现
household maximization
对课件第17页的个人理解
\[\max \ U_{0}= \int_0^{\infty} e^{-\rho t}L(t)u(c_{t})\,dt=\int_0^{\infty} e^{(n-\rho)t}u(c_{t})\,dt\] \[\text{s.t. } a' = w + (r-n)a - c\] \[a(0)=a_{0}\ is \ given\]current-value Hamiltonian 方程:
\[H = u(c_{t})+m[w+(r-n)a-c]\] \[\text{s.t. } a' = w + (r-n)a - c\]necessary FOCs:
\[\frac{\partial H}{\partial c}=0=u'(c_{t})-m\] \[\frac{\partial H}{\partial m}=a'\] \[\frac{\partial H}{\partial a}=-m'+(\rho-n)m=m(r-n) \tag{*}\]$\tag{*}$
\[\lim_{ t\to \infty }e^{(n-\rho)t}m_{t}a_{t}=0\] \[\dot{a_{t}}=(r_{t}-n)a_{t}+w_{t}-c_{t}\] \[from (*):\frac{\dot{m_{t}}}{m_{t}}=-(r_{t}-\rho)\] \[u'(c_{t})=m\]以上是证明过程,和讲义有出入 下面使用讲义表述
\[H(a,c,\mu)=u_{t}+\mu(r_{t}-n)a_{t}+w_{t}-c_{t}\]得到
\[H_{c}=u'(c_{t})-\mu_{t}=0\tag{1}\] \[H_{a}=\mu_{t}(r_{t}-n)=-\dot{\mu_{t}+(\rho-n)\mu_{t}}\tag{2} \lim_{ t \to \infty } [e^{(n-\rho)t}\mu_{t}a_{t}]=0\tag{3}\] \[\dot{a_{t}}=(r_{t}-n)a_{t}+w_{t}-c_{t}\tag{4}\]因此:
\[\frac{\dot{\mu_{t}}}{\mu_{t}}=\rho-r_{t}\] \[u'(c_{t})=\mu_{t}\]凑:
\[{\frac{u''(c_{t})c_{t}}{u'(c_{t})} }\frac{\dot{c_{t}}}{c_{t}}=\frac{\dot{\mu_{t}}}{\mu_{t}}\]得
\[\frac{\dot{c_{t}}}{c_{t}}=\frac{1}{ε(c_{t})}(r_{t}-\rho)\] \[r_{t}=f'(k_{t})-\delta\] \[\frac{\dot{c_{t}}}{c_{t}}=\frac{1}{ε(c_{t})}(f'(k_{t})-\delta-\rho)\]